> Quest.A Discrete Mathematics professor has a class of students. Frustrated with their lack of discipline, he decides to cancel class if fewer than students are present when class starts.
Given the arrival time of each student, determine if the class is canceled.
> Input.Input Format
The first line of input contains , the number of test cases.
Each test case consists of two lines. The first line has two space-separated integers, (students in the class) and (the cancelation threshold). The second line contains space-separated integers () describing the arrival times for each student.
Note: Non-positive arrival times () indicate the student arrived early or on time; positive arrival times () indicate the student arrived minutes late.
> Output.Output Format
For each test case, print the word YES if the class is canceled or NO if it is not.
> solve주어진 학생들의 도착시간에 따라 출력을 합니다.
#include <math.h> #include <stdio.h> #include <string.h> #include <stdlib.h> #include <assert.h> #include <limits.h> #include <stdbool.h> int main(){ int t; scanf("%d",&t); //test times for(int a0 = 0; a0 < t; a0++){ int n; int k; int m=0; // m -> at on time student, angry : over then k. scanf("%d %d",&n,&k); //n -> students number, k -> cancelation threshold. int a[n]; for(int a_i = 0; a_i < n; a_i++){ scanf("%d",&a[a_i]); if(*(a+a_i) <= 0){ m+=1; } } printf("%s\n", (m >= k ? "NO" : "YES")); //so, output. } return 0; }
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